How Many Image of Size 1200*800 with 8 bit gray value can be stored in 64 MB Storage space?

Question: How Many Images of Size 1200*800 with 8-bit gray value can be stored in 64 MB Storage space?

Solutions

Gray Level =8 bits   2^m

2³

The number of bits necessary to store the image is

bits = N*M*m
=1200*800*3
=2880000 bits
Converts bits into MB
2880000/1024*1024*8
= 0.03337 MB
So if we have 64 MB of Storage then
64
———
0.03337

=1917.89032
approximately 1918 image can be stored.